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SQuizL - Guess the SQL statement

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= fc.family_name
APPLY ( SELECT
COUNT (*) = 1
CROSS JOIN
DISTINCT
EXISTS ( SELECT
f1_teams ft ON
fc INNER JOIN
fc.*,
fc.team_id =
FIRST
ft.id AND ft.name
IN ( ft.name,
JOIN LATERAL
JOIN TO ONE
LEFT JOIN f1_teams
LIKE 'B%' OR
NATURAL
ONLY
QUALIFY RANK ()
SELECT * FROM
SINGLE REFERENCE
UNIQUE
USING ( team_id,

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